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0=-16x^2+195x-87
We move all terms to the left:
0-(-16x^2+195x-87)=0
We add all the numbers together, and all the variables
-(-16x^2+195x-87)=0
We get rid of parentheses
16x^2-195x+87=0
a = 16; b = -195; c = +87;
Δ = b2-4ac
Δ = -1952-4·16·87
Δ = 32457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-195)-\sqrt{32457}}{2*16}=\frac{195-\sqrt{32457}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-195)+\sqrt{32457}}{2*16}=\frac{195+\sqrt{32457}}{32} $
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